2n^2-29n+14=0

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Solution for 2n^2-29n+14=0 equation: 



2n^2-29n+14=0

a = 2; b = -29; c = +14;
Δ = b2-4ac
Δ = -292-4·2·14
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-27}{2*2}=\frac{2}{4}
=1/2
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+27}{2*2}=\frac{56}{4}
=14
$

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